## The giant planets, the lunar year and the Sun

Posted: December 11, 2019 by oldbrew in Cycles, Maths, moon, solar system dynamics
Tags: , ,

Jupiter-Saturn-Earth orbits chart

This was just about to go live when a new idea involving the Sun cropped up, now added to the original. The source data is from NASA JPL as usual.

From our 2015 de Vries post we saw that the 2503 year period, which the numbers were based on, consisted of 85 Saturn and 211 Jupiter orbits [see chart on the right].

Taking Saturn’s orbit period, and using JPL’s planetary data we find:
10755.7 days * 85 = 914234.5 days

The lunar year is 13 lunar orbits of Earth:
27.321582 days * 13 = 355.18056 days

914234.5 / 355.18056 = 2573.9992 (2574) = 13 * 198 lunar years

Number of beats of Saturn and the lunar year = 2574 – 85 = 2489 in 2503 years.
2503 – 2489 = 14
Number of Jose cycles in 2503 years = 14 (= 126 Jupiter-Saturn conjunctions, i.e. 9 J-S * 14).

Therefore the difference per Jose cycle between ‘Saturn-lunar year’ beats and Earth years is exactly one.

This can be confirmed by referring to the Saturn-Earth conjunctions in the same post.
In 2503 years there are 2418 S-E, so:
2503 – 2418 = 85 Saturn orbits
2489 – 2418 = 71
2503 – 2489 = 14
71 + 14 = 85

Repeating the exercise, for Jupiter:
Number of beats of Jupiter and the lunar year = 2574 – 211 = 2363 in 2503 years.
2503 – 2363 = 140
Ratio of 140:14 = 10:1 (J:S)

Therefore the difference per Jose cycle between ‘Jupiter-lunar year’ beats and Earth years is exactly ten.

Cross-check: 140 J beats – 14 S beats = 126 = number of J-S conjunctions in the period.
– – –
That was going to be the end of the post, but then something else turned up…

Bring on the Sun

Richard Christopher Carrington determined the solar rotation rate from low latitude sunspots in the 1850s and arrived at 25.38 days for the sidereal rotation period.Wikipedia

The lunar year was 13 lunar orbits (or rotations) = 355.18056 days.
An equivalent solar year is 14 * 25.38 days = 355.32 days.

As shown above, the number of lunar years in the 2503 sidereal year cycle of Jupiter and Saturn is 2574.
The number of solar years in the same period is 2573.
The difference of 1 in effect defines the cycle.

Rotations: 2573 * 14 solar = 2574 * 13 lunar. the being:
Difference: 36022 solar – 33462 lunar = 2560.

2574 – 2560 = 14 = the number of Jose cycles in the period.

So we propose that these figures offer links between the Sun, Moon, Earth, Jupiter and Saturn in terms of known repeating time periods. Something for theorists to consider perhaps.
– – –
Footnote – see:
Why Phi? – solar and lunar rotation
Posted: October 28, 2017
Solar: 25.38 days * 197 = 4999.860 d
Lunar: 27.321662 * 183 = 4999.864 d
. . .
Taking these as equivalent, we have 197-183 = 14 ‘beats’.

– – –
Each beat is 44/45 tropical years (TY).
2560*(44/45) = 2503.111 TY = ~2503.014 sidereal years [see chart at top of post].

1. oldbrew says:

What started this off was finding that 7 Jupiter-Saturn conjunctions = 143 lunar years.

(S*J) / (S-J) = 19.865036 sidereal years
https://ssd.jpl.nasa.gov/?planet_phys_par

143*13*27.321582 = 50790.82 days
(50790.82 / 7) / 365.25636 = 19.865037 sid. yrs.

The Moon has an orbital period of 27.321582 days
https://www.universetoday.com/19424/the-moon/

2. Reblogged this on Climate- Science.press.

3. oldbrew says:

‘As shown above, the number of lunar years in the 2503 sidereal year cycle of Jupiter and Saturn is 2574.
The number of solar years in the same period is 2573.’

2573 – 2503 = 70
70 / 14 = 5

Therefore solar years exceed sidereal years by exactly 5 per Jose cycle.

UPDATE: so solar years exceed sidereal years by one per one-fifth of the Jose cycle (~35.76 years = ~36.76 solar years), reminiscent of Landscheidt’s ‘five-fingered hand’ theory…

Figure 2: The Sun’s dynamics displays five-fold symmetry, thought to be reserved to the realm of life. “Big hands” with “big fingers” emerge, when the 9-year running variance of the Sun’s orbital angular momentum is plotted. Big hands and big fingers cover cycles o/solar activity with mean lengths of 178.8 years and 35.8 years, which are reflected in terrestrial cycles

Another version:

FIG. 2. Smoothed 9-year running variance in the angular momentum of the sun’s motion about the center of mass of the solar system (v), for the period 700-1600. The cyclic pattern, formed by the curve, conveys the impression of five-fingered (pentadactyl) hands. Fingers 3 and 5 point to minima in the 80-year sunspot cycle, the epochs of which are marked by triangles. Fingers 1, 2, and 4 indicate secular maxima; respective epochs of intense solar activity are indicated by arrows. Perturbation of the penta-rhythm seems to induce stability. Tlie rightmost hand, lacking a finger, coincides with the Sporer minimum.

http://bourabai.kz/landscheidt/relationship.htm

4. Paul Vaughan says:

Learning How 2 Take a Hit
4 Piece Sand Trust

=
We come from the land dove the eye sand SKnow
We’11 drive R ships 2 new lands
to Right the horde, and sing and cry
Valha11a: on We sweep with threshing oar

R only goAI wi11 be:
The West Turn Sure

how soft Eur. Fields so green
Can. whisper tale Sov. Gore

of how We calmed the tides of war

We R
Eur. over…….so now EU’d bet R stop
re-billed AI Eur. RU wins
4π22a’n’trust Can. win the day
=
“Eye MI-Grant Song” – Led_22a_PaIin

_ = base

11_10 = 13_8
22_10 = 26_8
44_10 = (2*26)_8=(130/2)_8
88_10 = 130_8
176_10 = 260_8
352_10 = (2*260)_8=(1300/2)_8
704_10 = 1300_8

9_10 = 11_8
18_10 = 22_8
36_10 = 44_8

72_10 = 110_8
144_10 = 220_8
288_10 = 440_8

73_10 = 111_8
146_10 = 222_8
292_10 = 444_8
584_10 = 1110_8

5256_10 = (111*11*10)_8
5256_10 = (2*2*111*11*2)_8

0.628323779737571 = (29.4474984673838)*(0.615197263396975) / (29.4474984673838 – 0.615197263396975)
0.602607984102782 = (29.4474984673838)*(0.615197263396975) / (29.4474984673838 + 0.615197263396975)
1.20521596820556 = (29.4474984673838)*(0.615197263396975)/((29.4474984673838+0.615197263396975)/2)

1.0351711566943 = (29.4474984673838)*(1.00001743371442) / (29.4474984673838 – 1.00001743371442)
0.967172886691895 = (29.4474984673838)*(1.00001743371442) / (29.4474984673838 + 1.00001743371442)
1.93434577338379 = (29.4474984673838)*(1.00001743371442)/((29.4474984673838+1.00001743371442)/2)

1.59868955949704 = (1.0351711566943)*(0.628323779737571) / (1.0351711566943 – 0.628323779737571)
0.390997675799726 = (1.0351711566943)*(0.628323779737571) / (1.0351711566943 + 0.628323779737571)
0.781995351599453 = (1.0351711566943)*(0.628323779737571)/((1.0351711566943+0.628323779737571)/2)

1.59868955949705 = (0.967172886691895)*(0.602607984102782) / (0.967172886691895 – 0.602607984102782)
0.371278637911561 = (0.967172886691895)*(0.602607984102782) / (0.967172886691895 + 0.602607984102782)
0.742557275823122 = (0.967172886691895)*(0.602607984102782)/((0.967172886691895+0.602607984102782)/2)

⌊ 1.59868955949705 / 0.781995351599453 ⌉ = ⌊2.04437220275948⌉ = 2
1.59868955949705 / 2 = 0.799344779748523
harmonic of 1.59868955949705 nearest 0.781995351599453 is 1.59868955949705 / 2 = 0.799344779748523
36.0290781181824 = (0.799344779748523)*(0.781995351599453) / (0.799344779748523 – 0.781995351599453)

⌊ 1.59868955949705 / 0.390997675799726 ⌉ = ⌊4.08874440551896⌉ = 4
1.59868955949705 / 4 = 0.399672389874261
harmonic of 1.59868955949705 nearest 0.390997675799726 is 1.59868955949705 / 4 = 0.399672389874261
18.0145390590912 = (0.399672389874261)*(0.390997675799726) / (0.399672389874261 – 0.390997675799726)

⌊ 1.59868955949705 / 0.195498837899863 ⌉ = ⌊8.17748881103791⌉ = 8
1.59868955949705 / 8 = 0.199836194937131
harmonic of 1.59868955949705 nearest 0.195498837899863 is 1.59868955949705 / 8 = 0.199836194937131
9.0072695295456 = (0.199836194937131)*(0.195498837899863) / (0.199836194937131 – 0.195498837899863)

5. oldbrew says:

From a 1904 newspaper article:

BRUCKNER’S CYCLE.
The most serious attempt to handle the
question has been made by Bruckner, of
Vienna, who was led to his investigation by
consideration of the variations that take
place in the level of the Caspian Sea, which
acts as a great rain-gauge for its vast drain-
age areas. He found that there was a re-
gular cycle in its rise and fall, the average
duration of a complete cycle being from 34
to 36 years.
The records go back to the
tenth, and are complete since the eighteenth
century. Bruckner found that the levels of
other inland lakes, with no outlets, varied
in cycles of the same length, reaching their
maximum at about the same dates as the
Caspian. He then considered the rainfall
of 321 localities, some of which he records
for over two centuries, and discovered that
the variation of the lakes was a result of
the variation in the rainfall. Bruckner also
found that from 1736 to 1885 there was the
same 34 or 35 years’ cycle of variation in
temperature. The date at which the rivers
of Northern Russia and Siberia are opened
to trade by the melting of the ice becomes
alternately earlier and later, the snouts of
the Alpine glaciers advance and recede, and
the beginning of the grape harvest in
France, Southern Germany, and Switzerland
varies, the movement in each case indicat-
ing the same 34-35 years’ cycle. Bruckner
also claims that the price of grain, looked
at broadly shows the sime vicissitudes as
the various meteorological factors which
control it. The weather cycle thus estab-
lished is not invariable in length, and it
does not affect the whole world similarly
and simultaneously. The cycle has varied
in different centuries from 34 to 35 to 36
years.
It is inevitable that there will
be irregularities, which will be exaggerated
in appearance by the artificial divisions and
annual weather records. When the ex-
treme sensitiveness of the atmosphere is
considered it is surprising, Professor Gre-
gory thinks, that only 8 per cent. of Bruck-
ner’s material gave discordant results, the
most important of the apparent insonsis-
tencies being due to obvious geographical
causes.
. . .
CONCLUDING REMARKS.
This 35-year period was recognised centu-
ries ago. Bacon’s essay on the “Vicissitudes
of Things” announces the old Dutch belief
in a 35 years’ cycle.